jQuery Ajax 简单的实现跨域请求
html 代码清单：
- <script type="text/javascript" src="http://www.youxiaju.com/js/jquery-1.4.2.min.js"></script>
- <script type="text/javascript">
- $(function(){
- $.ajax(
- {
- type:’get',
- url : 'http://www.youxiaju.com/validate.php?loginuser=lee&loginpass=123456',
- dataType : 'jsonp',
- jsonp:"jsoncallback",
- success : function(data) {
- alert("用户名："+ data.user +" 密码："+ data.pass);
- },
- error : function() {
- alert('fail');
- }
- }
- );
- })
- </script>
服务端 validate.php 代码清单：
- <?php
- header('Content-Type:text/html;Charset=utf-8');
- $arr = array(
- "user" => $_GET['loginuser'],
- "pass" => $_GET['loginpass'],
- "name" => 'response'
- );
- echo $_GET['jsoncallback'] . "(".json_encode($arr).")";
效果图：
from:http://blog.csdn.net/liruxing1715/article/details/18707605